Unit I: Vedic Math, Number System, Average - PEA305 Analytical Skills-I | B.Tech CSE Notes PDF | FineNotes4U


Unit I: Vedic Math, Number System, Average


⭐Vedic Math:


Multiplication of Two 2-Digit Numbers

Steps:

  1. Write the Numbers: Arrange the numbers vertically.

    Example:

      21
    x 23
    
  2. Multiply Ones Place: Multiply the digits in the ones place and place the product under the line.

      1 × 3 = 3
    
  3. Cross Multiply and Add:

    • Multiply the tens digit of the first number with the ones digit of the second number.
    • Multiply the ones digit of the first number with the tens digit of the second number.
    • Add the two products.
      (2 × 3) + (1 × 2) = 6 + 2 = 8
    
  4. Multiply Tens Place: Multiply the tens digits and place the result to the left.

      2 × 2 = 4
    

Thus, the answer for 21 × 23 is 483.

Special Case:

If both numbers end in 1, the middle term can be simplified by adding the tens digits:

Example:

  41 × 81

Instead of cross multiplying:

  4 × 8 / (8 + 4) / 1 = 3321

Multiplication of Two 3-Digit Numbers

Consider numbers ABC and DEF:

  ABC
  x DEF

Steps:

  1. Multiply the last digits: C × F.
  2. Cross multiply B × F and C × E; add any carry from step 1.
  3. Multiply A × F, B × E, C × D; add any carry from step 2.
  4. Multiply A × E and B × D; add any carry from step 3.
  5. Multiply A × D; add any carry from step 4.

Example:

  234 × 651
  2×6/6×3+2×5/3×5+6×4+2×1/4×5+3×1/4×1
  Answer: 152334

Squaring Numbers

Different Methods Based on Ranges:

  1. Numbers Ending in 5:

    • Remove 5 and multiply the remaining number by its successor.
    • Append 25 at the end.
    • Example: 65² → 6 × 7 = 42 → Answer: 4225
  2. Numbers from 25-50:

    • Calculate difference (d) from 50.
    • First part: (25 - d), Second part: d².
    • Example: 46² → (25 - 4) / 4² = 2116
  3. Numbers from 50-75:

    • First part: (25 + d), Second part: d².
    • Example: 54² → (25 + 4) / 4² = 2916
  4. Numbers from 75-100:

    • First part: (100 - 2d), Second part: d².
    • Example: 94² → (100 - 12) / 6² = 8836
  5. Numbers from 100-125:

    • First part: (100 + 2d), Second part: d².
    • Example: 113² → (100 + 26) / 13² = 12769

Square Root Calculation

Steps:

  1. Group digits in pairs from right.
  2. Find the nearest square to the first group.
  3. Determine the unit's digit based on the square endings.
  4. Multiply the ten's digit by its next number and compare.

Example:

√784
Grouping: 7 84
Tens digit: 2 (√4)
Unit digit possibilities: 2 or 8
Final Answer: 28

Cube Root Calculation

Steps:

  1. Group digits in sets of three from right.
  2. Find the nearest cube root.
  3. Use the last digit to determine the unit's place using complements.

Example:

Cube root of 54872:
Grouping: 54 872
Tens digit: 3 (since nearest cube root is 27)
Unit digit: 8 (from cube root complements)
Answer: 38

Squaring Tricks

Example:

Number: 306
Sub-base: 300

Step 1: 3 × (306 + 6) = 3 × 312 = 936
Step 2: 6² = 36
Answer: 93636

Another Example:

Number: 480 (sub-base 500)
480 - 20 = 460
5 × 460 = 2300
20² = 400
Answer: 230400
 

⭐Number System:


  1. Natural Numbers
    These are the numbers 1, 2, 3, 4, 5,... that represent counting numbers.
    Example: 1, 2, 3, 4, 5, 6, 7, ...

  2. Whole Numbers
    Whole numbers include all natural numbers plus zero.
    Example: 0, 1, 2, 3, 4, 5, 6, 7,...

  3. Integers
    Integers include all positive whole numbers, negative whole numbers, and zero.
    Example: -3, -2, -1, 0, 1, 2, 3, 4, ...

  4. Rational Numbers
    These are numbers that can be expressed in the form of a fraction pq\frac{p}{q}, where p and q are integers, and q0q \neq 0.
    Example: 41,35,5,72\frac{4}{1}, \frac{3}{5}, 5, -\frac{7}{2} etc.
    Note: Any number that terminates or repeats after the decimal point is a rational number.
    Example:

    • 34=0.75\frac{3}{4} = 0.75 (terminating)
    • 23=0.666...\frac{2}{3} = 0.666... (repeating)
  5. Irrational Numbers
    These are numbers that cannot be expressed as a fraction and have non-terminating and non-repeating decimal expansions.
    Example:

    • 2,3,π,e\sqrt{2}, \sqrt{3}, \pi, eetc.
  6. Real Numbers
    Real numbers are the set of all rational and irrational numbers.
    Example: 3,4,0.5,5,π-3, 4, 0.5, \sqrt{5}, \pi, etc.


Types of Numbers

  1. Even Numbers
    Numbers divisible by 2.
    Example: 2, 4, 6, 8, 10, 12, 14, ...

  2. Odd Numbers
    Numbers that are not divisible by 2.
    Example: 1, 3, 5, 7, 9, 11, 13, ...

  3. Prime Numbers
    Numbers greater than 1 with only two divisors: 1 and itself.
    Example: 2, 3, 5, 7, 11, 13, 17, ...

  4. Twin Primes
    A pair of prime numbers that differ by 2.
    Example: (3, 5), (5, 7), (11, 13), (17, 19), ...

  5. Co-prime Numbers
    Two numbers are co-prime if their greatest common divisor (GCD) is 1.
    Example:

    • GCD(9,28)=1\text{GCD}(9, 28) = 1, so (9, 28) are co-prime.
    • GCD(12,25)=1\text{GCD}(12, 25) = 1, so (12, 25) are co-prime.
  6. Composite Numbers
    These are natural numbers with more than two divisors.
    Example: 4, 6, 8, 9, 12, 14, 15, ...

  7. Perfect Numbers
    A number is perfect if the sum of its divisors (excluding itself) is equal to the number.
    Example:

    • 6: Divisors are 1, 2, 3. 1+2+3=61 + 2 + 3 = 6.
    • 28: Divisors are 1, 2, 4, 7, 14. 1+2+4+7+14=281 + 2 + 4 + 7 + 14 = 28.
    • 496, 8128 are also perfect numbers.
  8. Complex Numbers
    These are numbers of the form a+bi, where i=1i = \sqrt{-1}
    Example: 3+4i,56i3 + 4i, 5 - 6i, where ii represents the imaginary unit.


Face Value and Place Value

  1. Face Value
    The face value of a digit is simply the digit itself.
    Example:

    • In the number 6728, the face value of 6 is 6, the face value of 7 is 7, etc.
  2. Place Value
    The place value of a digit is the value it holds based on its position in the number.
    Example:

    • In the number 6729:
      • The place value of 9 = 9×1=99 \times 1 = 9
      • The place value of 2 = 2×10=202 \times 10 = 20
      • The place value of 7 = 7×100=7007 \times 100 = 700

Divisibility Rules

  • Divisibility by 2: A number is divisible by 2 if its last digit is 0, 2, 4, 6, or 8.
    Example:

    • 130, 128, 234 are divisible by 2.
  • Divisibility by 3: A number is divisible by 3 if the sum of its digits is divisible by 3.
    Example:

    • 65616561 → 6+5+6+1=186 + 5 + 6 + 1 = 18 (divisible by 3)
    • 1728117281 → 1+7+2+8+1=191 + 7 + 2 + 8 + 1 = 19 (not divisible by 3)
  • Divisibility by 5: A number is divisible by 5 if its last digit is either 0 or 5.
    Example: 100, 125, 895.


LCM and HCF

  • HCF (Highest Common Factor)
    The greatest number that divides two or more numbers exactly.
    Example:

    • HCF of 12 and 36 is 12.
    • HCF of 15 and 25 is 5.
  • LCM (Lowest Common Multiple)
    The smallest number that is divisible by two or more numbers.
    Example:

    • LCM of 4 and 6 is 12.
    • LCM of 5 and 8 is 40.

Factorization and Factors

  • Factors: Numbers that divide a given number exactly without leaving a remainder.
    Example:

    • Factors of 12 are 1, 2, 3, 4, 6, 12.
  • Prime Factorization: Expressing a number as a product of its prime factors.
    Example:

    • Prime factorization of 60 is 22×3×52^2 \times 3 \times 5.

Factorials and Trailing Zeros

  • Factorial
    The product of all positive integers from 1 to n.
    Example:

    • 4!=4×3×2×1=244! = 4 \times 3 \times 2 \times 1 = 24
    • 5!=5×4×3×2×1=1205! = 5 \times 4 \times 3 \times 2 \times 1 = 120
  • Trailing Zeros in Factorials
    The number of zeros at the end of a factorial depends on the number of times 10 is a factor in the number.
    Example:

    • Trailing zeros in 102!102!: 1025+10225=20+4=24\frac{102}{5} + \frac{102}{25} = 20 + 4 = 24.
      So, 102!102! has 24 trailing zeros.

Unit Digits

  • Unit Digit of Products
    Multiply the unit digits of the numbers.
    Example:

    • For 121×76×528×172, 1×6×8×2=961 \times 6 \times 8 \times 2 = 96, so the unit digit is 6.
  • Unit Digit of Powers
    Use the cyclicity of powers to find the unit digit.
    Example:

    • Unit digit of 2492^{49}:
      The unit digits of powers of 2 repeat in a cycle of 4:
      2,4,8,62, 4, 8, 6.
      Dividing 49 by 4 gives a remainder of 1, so 2492^{49} has the unit digit 2.

⭐Average


The average is a measure of central tendency, representing the sum of a set of quantities divided by the number of quantities. It provides a way to summarize a group of numbers with a single value.

Formula for Average

Average=Sum of all quantitiesNumber of quantities\text{Average} = \frac{\text{Sum of all quantities}}{\text{Number of quantities}}

Example:

If the ages of 4 students are 20 years, 22 years, 18 years, and 24 years, the average age can be calculated as:

Average Age=20+22+18+244=844=21years\text{Average Age} = \frac{20 + 22 + 18 + 24}{4} = \frac{84}{4} = 21 \, \text{years}

Important Properties of Average

  1. Increased by a constant (a):
    If all the numbers in a data set are increased by a constant aa, the average is also increased by aa.

    • Example: If all numbers are increased by 3, the new average is the old average + 3.
  2. Decreased by a constant (a):
    If all the numbers are decreased by a constant aa, the average is also decreased by aa.

    • Example: If all numbers are decreased by 4, the new average is the old average - 4.
  3. Multiplied by a constant (a):
    If all the numbers are multiplied by a constant aa, the average is also multiplied by aa.

    • Example: If all numbers are multiplied by 2, the new average is the old average × 2.
  4. Divided by a constant (a):
    If all the numbers are divided by a constant aa, the average is also divided by aa.

    • Example: If all numbers are divided by 5, the new average is the old average ÷ 5.

Age and Average

  1. Effect of change in the average age:
    • If the average age of nn persons decreases by xx years, the total age of nn persons decreases by n×xn \times x years.
    • If the average age of nn persons increases by xx years, the total age of nn persons increases by n×xn \times x years.

Example:

The average age of 6 persons is increased by 2 years when one of them, aged 26 years, is replaced by a new person. What is the age of the new person?

  • Solution:
    • Increase in total age = 6×2=126 \times 2 = 12 years.
    • Age of new person = 26 + 12 = 38 years.

The new person is 12 years older than the person who was replaced.


Average of Important Series of Numbers

Here are some useful formulas for calculating the average of different types of number series:

  1. Average of first nn natural numbers:

    Average=n+12\text{Average} = \frac{n + 1}{2}
    • Example: For n=5n = 5, the average is 5+12=3\frac{5 + 1}{2} = 3.
  2. Average of first nn consecutive even numbers:

    Average=n+12\text{Average} = \frac{n + 1}{2}
    • Example: For the first 4 even numbers (2, 4, 6, 8), the average is 4+12=5\frac{4 + 1}{2} = 5.
  3. Average of first nn consecutive odd numbers:

    Average=n\text{Average} = n
    • Example: For the first 4 odd numbers (1, 3, 5, 7), the average is 44.
  4. Average of consecutive numbers:

    Average=First Number+Last Number2\text{Average} = \frac{\text{First Number} + \text{Last Number}}{2}
    • Example: For the series 1, 2, 3, 4, 5, the average is 1+52=3\frac{1 + 5}{2} = 3.
  5. Average of squares of natural numbers till nn:

    Average=(n+1)(2n+1)6\text{Average} = \frac{(n + 1)(2n + 1)}{6}
    • Example: For n=3n = 3, the average of squares of first 3 natural numbers (1² + 2² + 3²) is (3+1)(2×3+1)6=4×76=286=4.67\frac{(3 + 1)(2 \times 3 + 1)}{6} = \frac{4 \times 7}{6} = \frac{28}{6} = 4.67.
  6. Average of cubes of natural numbers till nn:

    Average=n(n+1)24\text{Average} = \frac{n(n + 1)^2}{4}
    • Example: For n=3n = 3, the average of cubes of first 3 natural numbers (1³ + 2³ + 3³) is 3×(3+1)24=3×164=12\frac{3 \times (3 + 1)^2}{4} = \frac{3 \times 16}{4} = 12.
  7. Correct Sum:

    Correct Sum=Wrong Sum+(Right ValueWrong Value)\text{Correct Sum} = \text{Wrong Sum} + (\text{Right Value} - \text{Wrong Value})

Advanced Average Formulas

  1. Average of squares of first nn consecutive even numbers:

    Average=2(n+1)(2n+1)3\text{Average} = \frac{2(n + 1)(2n + 1)}{3}
  2. Average of squares of consecutive even numbers from 1 to nn:

    Average=(n+1)(n+2)3\text{Average} = \frac{(n + 1)(n + 2)}{3}
  3. Average of squares of consecutive odd numbers from 1 to nn:

    Average=n(n+2)3\text{Average} = \frac{n(n + 2)}{3}
  4. Average of combined observations:
    If the average of n1n_1 observations is a1a_1 and the average of n2n_2 observations is a2a_2, then the average of all observations is:

    A=n1a1+n2a2+n3a3+n1+n2+n3+A = \frac{n_1 a_1 + n_2 a_2 + n_3 a_3 + \dots}{n_1 + n_2 + n_3 + \dots}
  5. Average of remaining observations:
    If the average of mm observations is aa and the average of nn observations taken out of mm is bb, then the average of the remaining observations is:

    Average of remaining observations=manbmn\text{Average of remaining observations} = \frac{ma - nb}{m - n}

Average Speed

The average speed is the total distance traveled divided by the total time taken.

Average Speed=Total DistanceTotal Time\text{Average Speed} = \frac{\text{Total Distance}}{\text{Total Time}}
  1. For two equal distances at different speeds:
    If the distance between two points AA and BB is dd, and the speeds from AA to BB and from BB to AA are xx km/h and yy km/h, respectively, the average speed is given by:

    Average Speed=2xyx+y\text{Average Speed} = \frac{2xy}{x + y}

    Example:
    If a person travels two equal distances at 10 km/h and 30 km/h, the average speed is:

    Average Speed=2×10×3010+30=60040=15km/h\text{Average Speed} = \frac{2 \times 10 \times 30}{10 + 30} = \frac{600}{40} = 15 \, \text{km/h}
  2. For three equal distances at different speeds:
    If a person covers three equal distances at speeds AA, BB, and CC km/h, the average speed is:

    Average Speed=3ABCAB+BC+CA\text{Average Speed} = \frac{3ABC}{AB + BC + CA}
  3. For varying distances at different speeds:
    If a person covers PP part of the total distance at speed zz, QQ part at speed yy, and RR part at speed zz, the average speed is:

    Average Speed=xyzPyz+Qxz+Rxy\text{Average Speed} = \frac{xyz}{Pyz + Qxz + Rxy}



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